JAVA SCRIPT - Traversing the Results from querySelectorAll() with forEach() and call() - Web Development and Design | Tutorial for Java, PHP, HTML, Javascript JAVA SCRIPT - Traversing the Results from querySelectorAll() with forEach() and call() - Web Development and Design | Tutorial for Java, PHP, HTML, Javascript

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Sunday, December 23, 2018

JAVA SCRIPT - Traversing the Results from querySelectorAll() with forEach() and call()

Traversing the Results from query SelectorAll() with forEach() and call()


Problem

You want to use forEach() on the nodeList returned from a call to querySelector All().

Solution

You can coerce forEach() into working with a NodeList (the collection returned by querySelectorAll()) using the following:


// use querySelector to find all second table cells
var cells = document.querySelectorAll("td + td");
[].forEach.call(cells,function(cell) {
sum+=parseFloat(cell.firstChild.data);
});


EXPLAIN


 The forEach() is an Array method, and the results of querySelectorAll() is a NodeList, which is a different type of object than an Array. In the solution, to get forEach() to work with the NodeList, we’re calling the method on an empty array, and then using call() on the object to emulate the effect of an Array method on the NodeList, as if it were an actual array.

Simple, but there are drawbacks. Unless you convert the NodeList into an Array, the coercion is a one-shot that has to be repeated if you need to use the same functionality again. In addition, later in the code you may automatically try another Array method on the NodeList, only to have it fail because you didn’t use coercion

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